va rog mult!!! ajuta ti ma repede

Răspuns:
[tex]\frac{2-\sqrt{6}}{5\sqrt{3}}\\=\frac{2-\sqrt{6}}{5\sqrt{3}}\cdot\frac{\sqrt{3}}{\sqrt{3}}\\=\frac{\left(2-\sqrt{6}\right)}{5\sqrt{3}\sqrt{3}}\\=\frac{2\sqrt{3}-\sqrt{18}}{5\cdot3}\\=\frac{2\sqrt{3}-3\sqrt{2}}{15}[/tex]