Răspuns:
Explicație pas cu pas:
a) (x-2i)(x+2i)/[(x(x-2i)-(x-2i)]=(x-2i)(x+2i)/(x-2i)(x-1)=(x+2i)/(x-1)
b) x1,2=-5i±√-25+24/2=-5i±i/2
x1=-3i x2=-2i
(x+3i)(x+2i)(x-3i)(x+3i)=(x+2i)/(x-3i)
c) numaratorul x²+x+4+2i=x²-4i²+x+2i=(x+2i)(x-2i)+(x+2i)=(x+2i)(x-2i+1)
x²+4ix+x+4i²=x²+x+4i(x+i).......
