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(3x+2)^2-12x
(x-3)^2+3(2x-3)​


Răspuns :

(3x+2)^2-12x=9x^2+12x+4-12x=9x^2+4

(x-3)^2+3(2x+3)=x^2-6x+9+6x+9=x^2+18

Formule folosite:

(a+b)^2=a^2+2ab+b^2

(a-b)^2=a^2-2ab+b^2