Răspuns:
niuCH4: niuC2H6= 2: 5
V amestec= 78,4ml--->
---> niu, amestec= V/Vm= 78,4ml/22,4ml/mmol= 3,5mmol
in 3,5mmol amestec se gasesc:
2x3,5/7= 1mmol CH4
5X3,5/7=2,5mmol C2H6
1mmol......2mmol
CH4 + 2O2---> CO2+ 2H2O
V,O2= niuxVm= 2mmolx22,4 ml/mmol= 44,8 ml
1mmol.......3,5mmol
C2H6 + 7/2O2----> 2CO2 +3H2O
2,5mmol.........x=8,75mmolO2
V,O2=8,75x22,4ml=196ml
total V,O2=240,8ml
V aer= 240,8x100/20ml=1204ml=1,204m³
Explicație:
