Răspuns:
[tex] {4}^{37} \div (2 \times {2}^{71} ) + (3 + 3 \times 105) \div 106 = \\ ( {2}^{2} ) {}^{37} \div ( {2}^{1 + 71} ) + (3 + 315) \div 106 = \\ ({2}^{2 \times 37} ) \div {2}^{72} + 318 \div 106 = \\ {2}^{74} \div {2}^{72} + 3 = \\ {2}^{2} + 3 = \\ 4 + 3 = 7[/tex]
sper că te-am ajutat!
