se dau numerele:x=6²:3²-3 si y=(4³-2³):2³

Răspuns:
[tex]x = 6 {}^{2} \div 3 {}^{2} - 3 \\ x = 36 \div 9 - 3 \\ x = 4 - 3 \\ x = 1[/tex]
[tex]y = (4 {}^{3} - 2 {}^{3} ) \div 2 {}^{3} \\ y = (64 - 8) \div 8 \\ y = 56 \div 8 \\ y = 7[/tex]
=> x<y