a.
m.apa = 200 mL x 1g/mL = 200g
md = 8g
ms = md+m.apa = 200+8 = 208 g
c% = mdx100/ms
8x100/208 = 3,85%
b.
md2 = md1 + 8 = 8+8 = 16g
ms2 = ms1+8 = 208+8 = 216g
c2% = 16x100/216 = 7,4%
c.
ms3 = ms2+100 = 216+100 = 316g
c3% = 16x100/316 = 5,06%
d.
solutia initiala
ms = 208g , md = 8g
solutia obtinuta;
ms= 300+8 = 308g , md = 8g
=>
md.final = 8+8 = 16g
ms.final = 208+308 = 516g
=> c% = 16x100/516 = 3,1%
e.
notam cu a = masa de zahar adaugata
md2 = md1 + a = 8+a
ms2 = ms1 + a = 208+a
13,79 = (8+a)100/(208+a)
=> a = 2068,32/86,21 = 24 g zahar adaugat (rezultat rotunjit)
=> 24/8 = 3 pliculete de zahar vanilat
