Punctul a)
[tex]\displaystyle{ \frac{24}{8} = 3 }[/tex]
[tex]\displaystyle{ \frac{11}{55} = \frac{1}{5} = 0,2 }[/tex] (se simplifica prin 11)
[tex]\displaystyle{ \frac{169}{13} = 13 }[/tex] (169 = 13 x 13)
[tex]\displaystyle{ \frac{20}{400} = \frac{1}{20} = 0,05 }[/tex] (400 = 20 x 20)
Punctul b)
[tex]\displaystyle{ \frac{20}{\frac{2}{3}}= 20 \cdot \frac{3}{2} = \frac{60}{2} = 30 }[/tex]
[tex]\displaystyle{ \frac{0,13}{6,5} = \frac{1}{50} = 0,02 }[/tex]
[tex]\displaystyle{ \frac{\frac{27}{5}}{\frac{9}{20}}=\frac{27}{5} \cdot \frac{20}{9} = 3 \cdot 4 = 12 }[/tex] (se simplifica pe diagonala 27 cu 9 si ne da 3, si 20 cu 5 si ne da 4)
[tex]\displaystyle{ \frac{\frac{201}{2}}{\frac{561}{8}}=\frac{201}{2} \cdot \frac{8}{561} = \frac{268}{187} }[/tex]
Punctul c)
[tex]\displaystyle{ \frac{0,(6)}{0,(3)} = \frac{\frac{6}{9}}{\frac{3}{9}}=\frac{6}{9} \cdot \frac{9}{3} = 2}[/tex] (se reduce 9 cu 9 iar 6 : 3 = 2)
[tex]\displaystyle{ \frac{1,1(3)}{11,(3)}=\frac{\frac{113-11}{90}}{\frac{113-11}{9}}=\frac{102}{90} \cdot \frac{9}{102} = \frac{9}{90} = \frac{1}{10} = 0,1 }[/tex]
[tex]\displaystyle{ \frac{\frac{169}{33}}{5,(12)} = \frac{169}{33} : \frac{512-5}{99} = \frac{169}{33} \cdot \frac{99}{507} = 1}[/tex] (se simplifica pe diagonala 99 cu 33 si ne da 3, iar 3 x 169 = 507 deci 507/507 = 1)
[tex]\displaystyle{ \frac{2^{7}}{4^{3}}=2^{7} : (2^{2})^{3} = 2^{7} : 2^{6} = 2^{1} = 2 }[/tex] (l-am scris pe 4 ca 2²)
#copaceibrainly
