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ma poate ajuta cineva la 9?​

Ma Poate Ajuta Cineva La 9 class=

Răspuns :

[tex]\it a)\ a_1=6,\ \ a_2=5\\ \\ r = a_2-a_1=5-6=-1\\ \\ a_7=a_1+6r=6+6\cdot(-1)=6-6=0\\ \\ S_7=\dfrac{(a_1+a_7)\cdot7}{2}=\dfrac{(6+0)\cdot7}{2}=\dfrac{6\cdot7}{2}=21[/tex]

[tex]\it b)\ \ r=5,\ \ a_2+a_8=48 \Rightarrow a_2+a_2+6r=48 \Rightarrow 2a_2+6\cdot5=48 \Rightarrow \\ \\ \Rightarrow 2a_2+30=48|_{-30} \Rightarrow 2a_2=18|_{:2} \Rightarrow a_2=9\\ \\ a_{25}=a_2+23r=9+23\cdot5=9+115=124[/tex]

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