Răspuns:
Explicație pas cu pas:
[tex]log_{a^{n}} b=\frac{1}{n} log_{a} b[/tex]
[tex]\frac{1}{2} log_{2} x+\frac{1}{4} log_{2} x+ log_{2} x=7\\ \\ (\frac{1}{2}+\frac{1}{4}+1) log_{2} x=7\\ \\ \frac{7}{4} log_{2} x=7\\ \\ log_{2} x=7\cdot\frac{4}{7} \\ \\ log_{2} x=4\\ \\ x=2^{4} \\ \\ x=16[/tex]
