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sa se rezolve f(x)=0 f:R>R,f(x)=x^2+2x-3​

Răspuns :

Bună!

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[tex]\left \{ {{f:R->R, f(x)=x^{2}+2x-3 } \atop {f(x)=0}} \right. =>x^{2} +2x-3=0[/tex]

x²+2x-3=0

a=1

b=2

c=-3

Δ=b²-4ac=2²-4×1×(-3)=4+12=16>0 ⇒

          ⇒ [tex]x_{1} =\frac{-b-\sqrt{delta} }{2a} =\frac{-2-4 }{2} =\frac{-6}{2} =-3[/tex]

          ⇒ [tex]x_{2} =\frac{-b+\sqrt{delta} }{2a} =\frac{-2+4}{2} =\frac{2}{2} =1[/tex]

(x₁; x₂)=(-3; 1)