Răspuns:
100g compus........65,04g Br
123g.........................x
x= 80gBr
niu,Br= m/miu= 80/80mol-> 1mol Br in 1 mol compus
100g compus............(100-65,04)g C si H
123g.............................x
x= 43g C si H
daca compusul este saturat, are formula CnH2n+1Br si masa(C+H)=14n+1
14n+1=43---> n=3
compusul este CH3-CH2-CH2Br 1bromo-propan
N,E= [2+3(4-2) +7(1-2) +1(1-2)]/ 2= 0
IZOMER DE POZITIE CH3-CHBr-CH3 2 bromo-propan
Explicație:
