Răspuns:
Explicație:
a. oxigen Z=8 A=16 8p, 8e , 8n
16 g O
16 g O---------1 mol de atomi de O ----------------------6,023.10²³ atomi de O---
------ 8 . 6,023.10²³ p---- -----8 . 6,023.10²³ n
b. Fe
Z= 26 A=56 26p,26e,30n
11,2 kg Fe= 11200 g Fe
n= 11200g : 56g/moli=200moli de atomi de Fe
1mol Fe-----6,023.10²³atomi Fe--------26 . 6,023.10²³ p----30 . 6,023.10²³n
200moli Fe -----------------------------------------x----------------------------y
x= 200 . 26 . 6,023.10²³ p =
y= 200 . 30 .6,023.10²³ n =
c.
Mg
Z=12 A=24 12p , 12e , 12n
5kmoli=5000 moli
1mol Mg -------6,023.10²³atomi Mg------12 . 6,023.10²³ p-----12.6,023.10²³ n
5000 moli ------------------------------------------x----------------------------y
x=5000 . 12 . 6,023.10²³ p =3611380 .10²³ p
y=3611380. 10²³ n
d.
nH2= 2,24 L : 22,4 L /moli=0,1 moli
H Z=1 A=1 1p ,1e , 0 n
1mol H2----------6,023.10 ²³molecule H2----2 .6,023.10²³atomi H-----------------------------2 . 2 .6,023.10²³p-----------0 .2. 6,023.10²³ n
0,1 moli H2 ----------x-------------------------y
x= 0,1 . 2 . 2 .6,023 .10²³p =
y= 0
calculeaza , te rog , singur!
