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11,2g Fe reactioneaza cu o solutie de CuSO4. Determinati ce cantitate de Cu se depune, exprimata in grame si in moli.

Răspuns :

[tex]11,2g........................................x\\Fe + CuSO4 => FeSO4 + Cu\\56g.........................................64g\\\\x=\frac{11,2*64}{56}=12,8g\\\\[/tex]

[tex]n=\frac{m}{M}=\frac{12,8}{64}=0,2 moli[/tex]