repede!!!dau coroana la cel mai bun răspuns

a)
f(x)=0=>x=7
g(x)0=>x=1/3
b)
f(x)≥g(x)=>(x-7)/2≥3x-1=>x-7≥6x-2=>x-6x≥7-2=>-5x≥5=>x≤-1=>x€[-∞-1]=>
f(x)=0=>(x-7)/2=0=>x-7=0=>x=7=>
g(x)=0=>3x-1=0=>x=1/3