Subiectul 1
1.(-24):(-8)+(-2)^3=3+(-2)^3=-5^3=-125
2.triunghi echilateral
3.17 bile albe...33 bile roşii
17+33=50;50/17=0,34%=34%(probabilitate/nr cazuri probabile)
4.3/x=24/16 (folosind proprietatea mezilor şi extremilor,rezolvăm)
3/x=24/16;x=3*16/24;x=16/8;x=2
5. a/b=2/5 =>a/2=b/5=K => a=2K;b=5K
7*2K-2*5K/4*2K+3*5K =14K-10K/8K+15K =4K/23K =4/23
Subiectul 2
1. -2*(-3+x)=-14
-3+x=-14+2
-4x=-12
x=3
