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Help me, va rog!!!!!!!

Help Me Va Rog class=

Răspuns :

Salut,

[tex]\left(\dfrac{2}3\cdot x\sqrt x\right)^{'}=\left(\dfrac{2}3\cdot x^{1+1/2}\right)^{'}=\left(\dfrac{2}3\cdot x^{3/2}\right)^{'}=\dfrac{2}3\cdot\dfrac{3}2\cdot x^{3/2-1}=x^{1/2}=\sqrt x.[/tex]

Ai înțeles ?

Green eyes.