AJUTORRRRRRRRRRRRRRRRRRRRRRRRRRRRRR!!!!!!! În câte zerouri se termina (a+b) la puterea 2

a=10⁵⁹-9•10⁵⁸=10⁵⁸•(10-9)
a=10⁵⁸
b=5⁴•25¹¹•125¹⁰•2⁵⁶+2⁵⁷+2⁵⁸+2⁵⁹
b=5⁴•(5²)¹¹•(5³)¹⁰•2⁵⁶(1+2¹+2²+2³)
b=5⁴•5²²•5³⁰•2⁵⁶•15
b=5⁵⁶•2⁵⁶•15
b=10⁵⁶•15
(a+b)²=(10⁵⁸+10⁵⁶•15)²
(a+b)²=[10⁵⁶•(10²+15)]²
(a+b)²=10¹¹²•115²
=>112 zerouri