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H(x)=1/8x^3−x^2

Over which interval does h have a positive average rate of change?

Choose 1 answer:

(Choice A)

0≤x≤8

(Choice B)

6≤x≤8

(Choice C)

0≤x≤2

(Choice D)

0≤x≤6


Răspuns :

Răspuns:

x ≥ 8.

Explicație pas cu pas:

H(x)=1/8x^3−x^2 = x^2 (x/8 -1)

x^2 ≥ 0, ∀ x ∈ R ⇒

H(x) ≥ 0 ⇔ x/8 - 1 ≥ 0 ⇔ x/8 ≥ 1 ⇔ x ≥ 8